I expect most calculators online just run a subset of all possible boards as a representative sample - for example on ProPokerTools if you run a heads up hand against a random hand you get an exhaustive result (across 2,781,381,002,400 trials if running a random hand against a random hand - obviously less if a hand/range is specified for Hero), but if you run any hand/range against 2 or more random hands, you get a 600,000 trial sample. If we are 50% versus one random hand then against two random hands is 34% and three random hands is 21% with the calculators. I see poker calculators that do this very fast. Would I need to run combin(990,2) = 489,555? It seems like there has to be a trick to get results versus multiple random hands from knowing the value for one random hand. My question relates to matchups versus 2 random hands. If you are 50% against 1 random hand you cannot just divide by 2 and say you are 25% against 2 random hands. For each board, I run all the remaining 2 card hands combin(45,2) = 990 and just sum the wins and losses.Īgainst more than 1 random hand it get complicated though. I remove the two cards from the 52 card deck and run all the 5 card boards combin(50,5) = 2,118,760. Your two hole cards are combined with a common 5 card board to create the best 5 card hand. It works - I compared its results to a published list. I have written a program to rate 2 hole cards (your hand) against a single random hand.
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